CONVERTING FROM BASE TWO TO ANOTHER BASE (BINARY NUMBERS)
Subject:
MATHEMATICS
Term:
First Term
Week:
Week 1
Class:
JSS 3 / BASIC 9
Previous lesson: Pupils have previous knowledge of
BINARY OPERATIONS
that was taught in their previous lesson
Topic:
Number Bases:
- (a) Conversion from base ten to other bases.
- (b) Conversion from other bases to base ten.
- (c) Conversion from one base to another other than base ten. (d) Number base arithmetic.
Behavioural Objectives:
At the end of the lesson, learners will be able to
- conversion from base ten to other bases.
- conversion from other bases to base ten.
- conversion from one base to another other than base ten.
- solve simple sums on number base arithmetic.
Instructional Materials:
- Wall charts
- Pictures
- Related Online Video
- Flash Cards
Methods of Teaching:
- Class Discussion
- Group Discussion
- Asking Questions
- Explanation
- Role Modelling
- Role Delegation
Reference Materials:
- Scheme of Work
- Online Information
- Textbooks
- Workbooks
- 9 Year Basic Education Curriculum
- Workbooks
CONTENT:
WEEK 1
TOPIC: NUMBER BASES
CONTENT:
- Concept and types of number base.
- Binary numbers.
- Conversion in number bases: Denary to Binary, Binary to Denary, Denary to other bases, One base to another, etc.
- Arithmetical operation in Binary System: Addition, Subtraction, Multiplication and Division.
- Bidecimal numbers: Conversion, Addition and Subtraction.
- Equation in number bases.
CONCEPT AND TYPES OF NUMBER BASES
Number Base is a system of counting natural numbers in bundles. Some languages have their own unique method or way of counting numbers while others have same method. For instance, numbers are counted in bundle of ten digits called base ten or denary. The digits involved in English natural numbers are: 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.
Some unique number bases include: Base 2 (Binary), Base 8 (Octal), Base 10 (Denary or Decimal), Base 16 (Hexadecimal),… there are other bases such as base 3, base 4, base 5, base 6, etc. The bases of number systems are usually written as a subscript either in word or figure. Examples: 1110112 or 111011two, 57348 or 5734eight, 78110 or 781ten, etc.
CLASS ACTIVITY:
Teachers should ask the students to count in their mother tongues.
Good morning, class! Today, we’re going to learn about the conversion of binary numbers (base two numbers) to denary numbers (base 10 numbers). Understanding this topic is essential because it helps us communicate and work with binary systems used in computers and digital electronics.
Now, let’s start by revisiting what binary numbers are. Binary is a number system that only uses two digits: 0 and 1. In contrast, our familiar denary (base 10) system uses ten digits from 0 to 9. The positions of these digits in a number determine their value based on powers of 10.
For example, in the denary system:
– 123 = (1 * 10^2) + (2 * 10^1) + (3 * 10^0)
Now, let’s move on to converting binary to denary. To do this, we follow a straightforward process:
Step 1: Write down the binary number.
Step 2: Assign each binary digit a positional value from right to left. The rightmost digit has a positional value of 2^0 (which is 1), and the positional value increases by a power of 2 as we move from right to left.
Step 3: Multiply each binary digit by its positional value.
Step 4: Add all the products from Step 3 together to get the denary equivalent.
Let’s work through an example to make this clearer. We’ll convert the binary number 10110 to denary:
Step 1: Write down the binary number 10110.
Step 2: Assign positional values to each digit from right to left:
– 0 at the rightmost has a positional value of 2^0 = 1
– 1 next to the right has a positional value of 2^1 = 2
– 1 next to the left has a positional value of 2^2 = 4
– 0 next to the left has a positional value of 2^3 = 8
– 1 at the leftmost has a positional value of 2^4 = 16
Step 3: Multiply each binary digit by its positional value:
– 0 * 1 = 0
– 1 * 2 = 2
– 1 * 4 = 4
– 0 * 8 = 0
– 1 * 16 = 16
Step 4: Add all the products from Step 3 together:
0 + 2 + 4 + 0 + 16 = 22
So, the binary number 10110 is equal to the denary number 22.
Now, practice this method with various examples on your own, and you’ll become more comfortable with converting binary to denary numbers. Remember, practice makes perfect! If you have any questions, feel free to ask. Happy learning!
BINARY NUMBERS.
Binary numbers are a system of counting numbers in base two. In binary system, the greatest digit is 1 and the least or lowest is 0. Hence, the two digits available in binary numbers are 1 and 0. Binary numbers is the most important number bases because of its usage in computer. Examples of binary numbers are 111112, 1000001two, 01012, etc.
EXPRESSING BINARY AS SUM OF MULTIPLES
We can easily express any binary number as power of multiples of two as shown in the following examples.
- 110two 2 1 0)
- 11112 3 2 1) 0)
- 10001tw0 4 3 2) 1 0
CLASS ACTIVITY
Express each of the following as multiples of power of its base
(1) 1011two (2) 11000110two (3) 832ten (4) 890.701ten
(5)100.1001two (6) 4302.42six (7) 0.0247eight
Converting binary numbers to denary numbers:
Example 1: Convert 1010 from binary to denary.
Step 1: Write down the binary number 1010.
Step 2: Assign positional values from right to left: 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3 = 8.
Step 3: Multiply each binary digit by its positional value: 0 * 1 = 0, 1 * 2 = 2, 0 * 4 = 0, 1 * 8 = 8.
Step 4: Add the products from Step 3: 0 + 2 + 0 + 8 = 10.
So, the binary number 1010 is equal to the denary number 10.
Example 2: Convert 11011 from binary to denary.
Step 1: Write down the binary number 11011.
Step 2: Assign positional values from right to left: 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16.
Step 3: Multiply each binary digit by its positional value: 1 * 1 = 1, 1 * 2 = 2, 0 * 4 = 0, 1 * 8 = 8, 1 * 16 = 16.
Step 4: Add the products from Step 3: 1 + 2 + 0 + 8 + 16 = 27.
So, the binary number 11011 is equal to the denary number 27.
Example 3: Convert 1001101 from binary to denary.
Step 1: Write down the binary number 1001101.
Step 2: Assign positional values from right to left: 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16, 2^5 = 32, 2^6 = 64.
Step 3: Multiply each binary digit by its positional value: 1 * 1 = 1, 0 * 2 = 0, 1 * 4 = 4, 1 * 8 = 8, 1 * 16 = 16, 0 * 32 = 0, 1 * 64 = 64.
Step 4: Add the products from Step 3: 1 + 0 + 4 + 8 + 16 + 0 + 64 = 93.
So, the binary number 1001101 is equal to the denary number 93.
Example 4: Convert 11100 from binary to denary.
Step 1: Write down the binary number 11100.
Step 2: Assign positional values from right to left: 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16.
Step 3: Multiply each binary digit by its positional value: 0 * 1 = 0, 0 * 2 = 0, 1 * 4 = 4, 1 * 8 = 8, 1 * 16 = 16.
Step 4: Add the products from Step 3: 0 + 0 + 4 + 8 + 16 = 28.
So, the binary number 11100 is equal to the denary number 28.
Example 5: Convert 1010111 from binary to denary.
Step 1: Write down the binary number 1010111.
Step 2: Assign positional values from right to left: 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16, 2^5 = 32, 2^6 = 64.
Step 3: Multiply each binary digit by its positional value: 1 * 1 = 1, 1 * 2 = 2, 1 * 4 = 4, 0 * 8 = 0, 1 * 16 = 16, 1 * 32 = 32, 1 * 64 = 64.
Step 4: Add the products from Step 3: 1 + 2 + 4 + 0 + 16 + 32 + 64 = 119.
So, the binary number 1010111 is equal to the denary number 119.
Keep practicing these conversions, and you’ll become more confident in working with binary and denary numbers. If you have any questions, feel free to ask!
CONVERSION OF BINARY NUMBERS TO DECIMAL NUMBERS
To express binary numbers in decimals or denary, we write the binary number as a sum of multiples of powers of two, or we multiply each digit by the base and add to the next digit starting from the left.
NOTE: Any number or letter raised to the power of zero is 1
Examples:
- Convert 1111two to denary scale.
Solution:
1111two 3 2 1) 0)
ten.
- Express 11101two as a decimal number
Solution:
11101two 4 3 2) 1 0
ten
- Convert 1111110two to a number in base ten.
Solution:
1111110two 6 5 4) 3 2
1 0
ten
CLASS ACTIVITY
Express the following binary numbers as denary numbers.
- 110111two 1010101010two 3. 10000000101two
CONVERSION OF OTHER NUMBER BASES TO DENARY
Converting other number bases to denary is the same as that of binary discussed earlier. Let’s study the examples below.
- Express 56eight to denary
Solution:
56eight 1 0 ten
- Convert 1243five to base ten
Solution:
1243five 3 2 1) 0)
ten
CLASS ACTIVITY
Express in denary the following number bases:
- 124eight 25seven 3. 48nine 4. 211five
CONVERSION FROM DENARY TO ANY BASE
In converting a denary number to base two (binary) or any other base, we divide by that new base keeping the remainder in each step until there is nothing more to divide. The result is the list of remainders from the last to the first.
Example:
- Convert 41ten to base five
- Convert 243ten to base eight
- Express 2610 as binary number
Solution:
5 | 41 | 8 | 243 | 2 | 26 | ||
5 | 8 R 1 | 8 | 30 R 3 | 2 | 13 R 0 | ||
5 | 1R3 | 8 | 3 R 6 | 2 | 6 R 1 | ||
0 R 1 | 0 R 3 | 2 | 3 R 0 | ||||
2 | 1 R 1 | ||||||
0 R 1 |
41ten five. 243ten eight 26ten two
CLASS ACTIVITY
Convert the following base ten numbers to the base indicated in brackets in front of each.
- 344(base 7) 3256(base 5) c. 7054(base 6) d. 106(base 2)
CONVERTING FROM ONE BASE TO ANOTHER BASE OTHER THAN BASE 10
To do this, two steps are involved:
Step1: convert the given base to base ten.
Step2: convert the result gotten from step1 above to the required base.
converting 123410 to 2
The equation calculation formula for 123410 number to 2 is like this below.
2|1234
2|617|0
2|308|1
2|154|0
2|77|0
2|38|1
2|19|0
2|9|1
2|4|1
2|2|0
2|1|0
2|1|1
Ans:100110100102
CONVERTING FROM ONE BASE TO ANOTHER BASE OTHER THAN BASE 10
We can convert from one base to another base, other than Base 10, using the following steps:
1. Convert the given number into its Base 10 equivalent.
2. Divide the Base 10 number by the new base.
3. Write down the remainder.
4. Divide the quotient by the new base.
5. Write down the remainder.
6. Repeat Step 4 until the quotient is equal to 0.
7. The remainders are the digits of the new number in reverse order.
For example, let’s convert the number “1234” from Base 10 to Base 2 (Binary).
1. 1234 = 1 x 10^3 + 2 x 10^2 + 3 x 10^1 + 4 x 10^0
2. 1234 / 2 = 617 Remainder 0
3. 617 / 2 = 308 Remainder 1
4. 308 / 2 = 154 Remainder 0
5.154 / 2 = 77 Remainder 0
6. 77 / 2 = 38 Remainder 1
7. 38 / 2 = 19 Remainder 0
8. 19 / 2 = 9 Remainder 1
9. 9 / 2 = 4 Remainder 1
10. 4 / 2 = 2 Remainder 0
11. 2 / 2 = 1 Remainder 0
12. 1 / 2 = 0 Remainder 1
13. The remainders in reverse order are 10011010010. Therefore, 1234 in Base 10 is equal to 10011010010 in Base 2 (Binary).
Now let’s convert the number “1234” from Base 10 to Base 8 (Octal).
1. 1234 = 1 x 10^3 + 2 x 10^2 + 3 x 10^1 + 4 x 10^0
2. 1234 / 8 = 308 Remainder 2
3. 308 / 8 = 38 Remainder 6
4. 38 / 8 = 4 Remainder 6
5. 4 / 8 = 0 Remainder 4
6. The remainders in reverse order are 2466. Therefore, 1234 in Base 10 is equal to 2466 in Base 8 (Octal).
Example:
- Convert 10111two to base 6
Solution:
Step1: we first convert 10111two to base ten.
10111two 4 3 2) 1 0
ten
Step2: we now convert 23ten to base 6
6 | 23 |
6 | 3 R 5 |
0 R 3 |
two 23ten six
- Convert 3041five to base four.
Solution:
First convert 3041five to base 10
3041five 3 2 1) 0
ten
Now, convert 395ten to base 4.
4 | 395 |
4 | 98 R 3 |
4 | 24 R 2 |
4 | 6 R 0 |
4 | 1 R 2 |
0 R 1 |
3041five 395ten 12023four
CLASS ACTIVITY
Convert: (a) 4056 to a binary number (b) 3214 to octal scale(c) 6548 to base three.
BICIMAL NUMBERS.
Bicimals are binary numbers in fractional form in which the denominator is a power of 2. Examples include 10.1012, 0.1112, 1011.11012, etc.
Good morning, class! Today, we’ll be diving into the topic of converting denary numbers (base 10) to binary numbers (base 2). This skill is essential because it helps us understand how computers and digital systems represent and process information using the binary number system.
Let’s begin with a quick recap of what denary and binary numbers are. In the denary system, we use ten digits from 0 to 9 to represent numbers. For example, the denary number 35 represents three tens and five units (3 * 10 + 5). On the other hand, the binary system only uses two digits: 0 and 1. Each digit’s position in a binary number represents a power of 2.
Now, let’s learn the step-by-step process of converting denary numbers to binary:
Step 1: Start with the given denary number.
Step 2: Divide the denary number by 2.
Step 3: Note the remainder (either 0 or 1) when dividing by 2, which represents the rightmost binary digit.
Step 4: Continue dividing the quotient from Step 2 by 2, noting the remainders each time, until the quotient becomes zero.
Step 5: Write the remainders obtained in reverse order to get the binary equivalent.
Let’s work through an example to illustrate the process. We’ll convert the denary number 13 to binary:
Step 1: Start with the denary number 13.
Step 2: Divide 13 by 2. The quotient is 6, and the remainder is 1.
Step 3: Write down the remainder (1) as the rightmost digit of the binary number.
Step 4: Divide the quotient (6) by 2. The new quotient is 3, and the remainder is 0.
Step 5: Write down the remainder (0) to the left of the previous digit.
Step 6: Divide the new quotient (3) by 2. The new quotient is 1, and the remainder is 1.
Step 7: Write down the remainder (1) to the left of the previous digits.
Step 8: Divide the new quotient (1) by 2. The quotient is now 0, and the remainder is 1.
Step 9: Write down the remainder (1) to the left of the previous digits.
Now, read the remainders in reverse order from Step 9 to Step 3:
Binary number = 1101
So, the denary number 13 is equivalent to the binary number 1101.
Great job, class! Now, practice this process with different denary numbers on your own to become more proficient in converting denary to binary. If you have any questions, don’t hesitate to ask. Happy learning!
CONVERSION OF BICIMAL TO DENARY
When converting a bicimal number to denary, the process is quite simple. All you need to do is take the value of each digit and multiply it by the corresponding power of two. For example, when converting the bicimal number 1101 (which has a value of 13 in denary), you would take 1 and multiply it by 2^3, take 1 and multiply it by 2^2, take 0 and multiply it by 2^1, and finally take 1 and multiply it by 2^0. When you add up all of these values, you get the final answer of 13.
Interestingly, this same process can be used to convert a denary number to bicimal. To do this, you simply take the value of each digit and divide it by the corresponding power of two. For example, when converting the denary number 13 to bicimal, you would take 1 and divide it by 2^3, take 1 and divide it by 2^2, take 0 and divide it by 2^1, and finally take 1 and divide it by 2^0. When you add up all of these values, you get the final answer of 1101 (which is 13 in bicimal).
In converting bicimal numbers to denary, we write the bicimal numbers as a sum of multiples of powers of two. The whole numbers parts of bicimal are raised to positive power of 2 increasing to the left starting with zero. While the fractional part are raised to negative power of 2 decreasing to the left starting with negative 1 .
101 . 1001
Whole number part Fractional number part
Examples:
Convert the following to denary:
- 112 b. 0.112 c. 111.0112
Solutions:
- 112 2 1 0) -1 -2
)ten oR ten.
- 112 0) -1) -2)
ten
- 0112 2 1 0) -1 -2 -3
ten ten.
NOTE: Other bases in fractional form other than bicimal can also be expressed in denary using the same method as in bicimal. Teacher should teach the students using the repeated method of converting number bases to base ten(denary).
EVALUATION:
Convert each of the following to denary scale.
- 10112 32568 c. 101.1012 d. 43.218 e. 32.215 f. 5329.
ARITHMETIC OPERATIONS IN NUMBER
Basic operations of addition, subtraction, multiplication and division are carried out in other bases exactly the same as base 10.
ADDITION IN BINARY SYSTEM
The binary number system is a base 2 system that uses only the digits 0 and 1 to represent all numbers. Because of its simplicity, the binary number system is used in many modern technologies, including computer hardware and software.
To add two binary numbers, start by aligning them on the right side so that their least significant digits are lined up. Then, add the numbers column by column, starting with the rightmost column. If the sum of a column is 2 or more, carry over the extra 1 to the next column.
For example, to add 101 + 100:
Align the numbers on the right side:
101
+ 100
_____
Start with the rightmost column and add the numbers:
101
+ 100
_____
001
The sum of the rightmost column is 1, so there is no need to carry over.
Move to the next column on the left and add the numbers:
101
+ 100
_____
0101
The sum of this column is 5, so carry over the 1 to the next column:
101
+ 100
_____
00101
Continue moving to the left and adding the numbers until all columns have been added:
101
+ 100
_____
11001
____
11
The final sum is 11001.
To add in binary number, the following steps are important:
- Arrange the numbers as in the addition of decimal numbers.
- Add the elements of the column starting with the right most column.
- Divide the sum by two.
- Record the remainder, which is either 0 or 1.
- Add the quotient to the sum of the next column and repeat the process for the next column.
NOTE:
. Teachers should explain addition principle in binary numbers to the students using appropriate illustrations.
Examples:
- Add 111two to 11two
Solution:
1 1 1
1 1
1 0 1 02
- 110112 101012 10012
Solution:
1 1 0 1 1
1 0 1 0 1
1 0 0 1
1 1 1 0 0 0 1two
ADDITION IN OTHER BASES:
The same principle applied when performing addition in binary and denary is applicable here also.
Examples:
- Add 40002five to 3403five
Solution:
4 0 0 0 2
+ 3 4 0 3
4 3 4 1 0five
- Find the sum of 2332four and 302four.
Solution:
2 3 3 2
+ 3 0 2
3 3 0 0four
- Table of addition in base nine:
0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | |
0 | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
1 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 10 |
2 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 10 | 11 |
3 | 3 | 4 | 5 | 6 | 7 | 8 | 10 | 11 | 12 |
4 | 4 | 5 | 6 | 7 | 8 | 10 | 11 | 12 | 13 |
5 | 5 | 6 | 7 | 8 | 10 | 11 | 12 | 13 | 14 |
6 | 6 | 7 | 8 | 10 | 11 | 12 | 13 | 14 | 15 |
7 | 7 | 8 | 10 | 11 | 12 | 13 | 14 | 15 | 16 |
8 | 8 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 |
NOTE: Teachers should solve more examples that includes adding in different bases, addition with missing numbers or digit in diferent bases.
CLASS ACTIVITY
Evaluate the following:
- 10112 2
- 1002 2 101112
- Find the sum of 2467 and 83610 give your answer in base seven.
- Find the missing numbers in the following sums in base two.
- 1 0 1 0 1 1 0 1 1
- * * * * * * * *
1 1 1 1 0 1 1 1 0
SUBTRACTION IN BASE TWO AND OTHER BASES
Subtractions in binary numbers are the same as subtraction in denary numbers. When the digit of the number to be subtracted is larger than the corresponding digit above it, we transfer one 2 from the next left column. If the immediate next column has zero digit, the transfer will be from further left column. The same principle is applicable to other bases other than base 2.
Examples:
- Subtract 1012 from 1112
Solution:
1 1 1
1 0 1
1 0two
- By how much is 3767eight greater than 2653eight?
Solution:
3 7 6 7
– 2 6 5 3
1 1 1 4eight
- Find the missing numbers in this subtraction in base 2
1 1 1 1 1 1
* * * * * *
1 0 1 0 1two
Solution:
We subtract 101012 from 1111112 to get the missing numbers.
Hence, 1111112 2 2
Therefore, the missing numbers is 2
- If 234five five 434five = 2304five, find
Solution:
= 2304five (234five 434five)
= 2304five (1223five)
= 1031five
NOTE: Teachers should explain this technique used in examples3 and 4 above with more examples.
MULTIPLICATION AND DIVISION OF NUMBER BASES
MULTIPLICATION is a repeated addition. This principle is always applied while multiplying binary numbers and other number bases. The important thing we must note is that if we are working in base two and other bases, all the figures we use in the working should be less than 2 or the number base under consideration.
Examples:
- Simplify 11012 1112
Solution:
1 1 0 1
1 1 1
1 1 0 1
1 1 0 1
1 1 0 1
1 0 1 1 0 1 1two
11012 1112 1011011two
- Base 5 multiplication table.
0 | 1 | 2 | 3 | 4 | |
0 | 0 | 0 | 0 | 0 | 0 |
1 | 0 | 1 | 2 | 3 | 4 |
2 | 0 | 2 | 4 | 11 | 13 |
3 | 0 | 3 | 11 | 14 | 22 |
4 | 0 | 4 | 13 | 22 | 31 |
DIVISION in base two is very similar to division in base ten. If the two numbers are in the same base, we divide using the long division method. However, if both numbers are not in the same base, we convert to base ten and then to the base required before solving.
Examples:
- Divide 101002 by 1002
Solution:
Method1
Convert both numbers to base 10 and divide , then convert back to base 2.
101002 = 2010 and 1002 = 410
2010 10 = 510
510 = 1012
Method2:
Long division.
101
10100
100 100
100
100
000
101002 1002 = 1012
PRACTICE EXERCISE
- Find the product of the following
- 111012 and 1112 4156 and 546 c. 201011 and 1010
- Evaluate 1110102 10012
- Complete the table in base seven
1 | 2 | 5 | 6 | |
1 | 1 | 2 | 6 | |
2 | 2 | 4 | 13 | |
5 | 5 | 13 | 34 | |
6 | 6 | 51 |
ASSIGNMENT
- Express each of the following numbers in binary
- a) 234six b) 0.75ten c) 73.5nine
- Convert each of the following binary numbers to base ten.
- a) 100.1111 b) 111 111
- Convert each of the following base ten numbers to binary
- a) 623 b) 20 c) 112. 125
- Simplify 11two x 1011two – 111two.
- If 100two x y = 1100two, find the value of y.
PRESENTATION:
Step 1:
The subject teacher revises the previous topic
Step 2:
He or she introduces the new topic
Step 3:
The class teacher allows the pupils to give their own examples and he corrects them when the needs arise
[mediator_tech]
Evaluation
Question 1: Convert the denary number 47 to binary.
a) 101101
b) 101111
c) 110111
Question 2: Convert the binary number 11010 to denary.
a) 22
b) 26
c) 28
Question 3: The binary number system uses digits ______ and _______.
a) 0, 1
b) 1, 2
c) 0, 2
Question 4: Convert the denary number 95 to binary.
a) 1011010
b) 1011110
c) 1011111
Question 5: In the denary system, we use ______ digits from 0 to 9.
a) 5
b) 8
c) 10
Question 6: Convert the binary number 111001 to denary.
a) 49
b) 57
c) 63
Question 7: The binary equivalent of the denary number 15 is ______.
a) 1111
b) 1010
c) 1101
Question 8: Convert the denary number 123 to binary.
a) 1011010
b) 1111011
c) 1101110
Question 9: The binary number 10011 is equivalent to the denary number ______.
a) 8
b) 15
c) 19
Question 10: The denary equivalent of the binary number 100110 is ______.
a) 18
b) 38
c) 22
Question 11: Convert the denary number 56 to binary.
a) 110000
b) 111000
c) 101100
Question 12: The binary number 1101 is equivalent to the denary number ______.
a) 12
b) 13
c) 14
Question 13: Convert the denary number 75 to binary.
a) 1001010
b) 1001101
c) 1010110
Question 14: The denary equivalent of the binary number 11110 is ______.
a) 30
b) 31
c) 32
Question 15: The binary number system uses the base ______.
a) 5
b) 2
c) 10
Make sure to carefully read each question and select the correct option (a, b, or c) to complete the fill-in-the-blank statements. Good luck, and don’t hesitate to ask if you need any assistance!
Suggested Solution
Let’s go through the questions one by one and provide the detailed workings:
Question 1: Convert the denary number 47 to binary.
Solution:
Step 1: Divide 47 by 2. The quotient is 23, and the remainder is 1.
Step 2: Divide 23 by 2. The quotient is 11, and the remainder is 1.
Step 3: Divide 11 by 2. The quotient is 5, and the remainder is 1.
Step 4: Divide 5 by 2. The quotient is 2, and the remainder is 1.
Step 5: Divide 2 by 2. The quotient is 1, and the remainder is 0.
Step 6: Divide 1 by 2. The quotient is 0, and the remainder is 1.
Reading the remainders from bottom to top: 47 in binary is 101111.
Answer: b) 101111
Question 2: Convert the binary number 11010 to denary.
Solution:
11010 in binary can be expressed as:
(1 * 2^4) + (1 * 2^3) + (0 * 2^2) + (1 * 2^1) + (0 * 2^0) = 16 + 8 + 0 + 2 + 0 = 26
Answer: b) 26
Question 3: The binary number system uses digits ______ and _______.
Solution:
a) 0, 1
Answer: a) 0, 1
Question 4: Convert the denary number 95 to binary.
Solution:
Step 1: Divide 95 by 2. The quotient is 47, and the remainder is 1.
Step 2: Divide 47 by 2. The quotient is 23, and the remainder is 1.
Step 3: Divide 23 by 2. The quotient is 11, and the remainder is 1.
Step 4: Divide 11 by 2. The quotient is 5, and the remainder is 1.
Step 5: Divide 5 by 2. The quotient is 2, and the remainder is 1.
Step 6: Divide 2 by 2. The quotient is 1, and the remainder is 0.
Step 7: Divide 1 by 2. The quotient is 0, and the remainder is 1.
Reading the remainders from bottom to top: 95 in binary is 1011111.
Answer: c) 1011111
Question 5: In the denary system, we use ______ digits from 0 to 9.
Solution:
c) 10
Answer: c) 10
Question 6: Convert the binary number 111001 to denary.
Solution:
111001 in binary can be expressed as:
(1 * 2^5) + (1 * 2^4) + (1 * 2^3) + (0 * 2^2) + (0 * 2^1) + (1 * 2^0) = 32 + 16 + 8 + 0 + 0 + 1 = 57
Answer: b) 57
Question 7: The binary equivalent of the denary number 15 is ______.
Solution:
15 in binary can be expressed as:
(1 * 2^3) + (1 * 2^2) + (1 * 2^1) + (1 * 2^0) = 8 + 4 + 2 + 1 = 15
Answer: a) 1111
Question 8: Convert the denary number 123 to binary.
Solution:
Step 1: Divide 123 by 2. The quotient is 61, and the remainder is 1.
Step 2: Divide 61 by 2. The quotient is 30, and the remainder is 1.
Step 3: Divide 30 by 2. The quotient is 15, and the remainder is 0.
Step 4: Divide 15 by 2. The quotient is 7, and the remainder is 1.
Step 5: Divide 7 by 2. The quotient is 3, and the remainder is 1.
Step 6: Divide 3 by 2. The quotient is 1, and the remainder is 1.
Step 7: Divide 1 by 2. The quotient is 0, and the remainder is 1.
Reading the remainders from bottom to top: 123 in binary is 1111011.
Answer: b) 1111011
Question 9: The binary number 10011 is equivalent to the denary number ______.
Solution:
10011 in binary can be expressed as:
(1 * 2^4) + (0 * 2^3) + (0 * 2^2) + (1 * 2^1) + (1 * 2^0) = 16 + 0 + 0 + 2 + 1 = 19
Answer: c) 19
Question 10: The denary equivalent of the binary number 100110 is ______.
Solution:
100110 in binary can be expressed as:
(1 * 2^5) + (0 * 2^4) + (0 * 2^3) + (1 * 2^2) + (1 * 2^1) + (0 * 2^0) = 32 + 0 + 0 + 4 + 2 + 0 = 38
Answer: b) 38
Question 11: Convert the denary number 56 to binary.
Solution:
Step 1: Divide 56 by 2. The quotient is 28, and the remainder is 0.
Step 2: Divide 28 by 2. The quotient is 14, and the remainder is 0.
Step 3: Divide 14 by 2. The quotient is 7, and the remainder is 0.
Step 4: Divide 7 by 2. The quotient is 3, and the remainder is 1.
Step 5: Divide 3 by 2. The quotient is 1, and the remainder is 1.
Step 6: Divide 1 by 2. The quotient is 0, and the remainder is 1.
Reading the remainders from bottom to top: 56 in binary is 111000.
Answer: b) 111000
Question 12: The binary number 1101 is equivalent to the denary number ______.
Solution:
1101 in binary can be expressed as:
(1 * 2^3) + (1 * 2^2) + (0 * 2^1) + (1 * 2^0) = 8 + 4 + 0 + 1 = 13
Answer: b) 13
Question 13: Convert the denary number 75 to binary.
Solution:
Step 1: Divide 75 by 2. The quotient is 37, and the remainder is 1.
Step 2: Divide 37 by 2. The quotient is 18, and the remainder is 1
Step 3: Divide 18 by 2. The quotient is 9, and the remainder is 0.
Step 4: Divide 9 by 2. The quotient is 4, and the remainder is 1.
Step 5: Divide 4 by 2. The quotient is 2, and the remainder is 0.
Step 6: Divide 2 by 2. The quotient is 1, and the remainder is 0.
Step 7: Divide 1 by 2. The quotient is 0, and the remainder is 1.
Reading the remainders from bottom to top: 75 in binary is 1001011.
Answer: a) 1001011
Question 14: The denary equivalent of the binary number 11110 is ______.
Solution:
11110 in binary can be expressed as:
(1 * 2^4) + (1 * 2^3) + (1 * 2^2) + (1 * 2^1) + (0 * 2^0) = 16 + 8 + 4 + 2 + 0 = 30
Answer: a) 30
Question 15: The binary number system uses the base ______.
Solution:
b) 2
Answer: b) 2
Great job, class! You’ve successfully solved the fill-in-the-blank questions related to converting denary numbers to binary numbers. Keep practicing and exploring more topics in mathematics. If you have any more questions or need further clarification, feel free to ask. Happy learning!
[mediator_tech]
CONCLUSION:
The subject goes round to mark the pupil’s notes. He does the necessary corrections