Exam Questions Second Term SS 2 Further Mathematics

Further Mathematics SS 2 Second Term Examination Questions

Section A: Objective Questions (Fill in the Blanks)

  1. Given that x = -3 and y = -7, evaluate (x² – y) / (y² – x)
    a) -1/11
    b) 1/23
    c) 4/13
    d) 12/17

  2. Solve the equation x² – 2x – 8 = 0
    a) x = 0 or 12
    b) x = -2 or 4
    c) x = 2
    d) x = 2 or 4

  3. The conjugate of 2 + √3 is:
    a) 2
    b) √3
    c) √3 + 2
    d) 2 – √3

  4. If f(x) = 10x – 3, find f(2)
    a) 7
    b) 20
    c) 3
    d) 17

  5. Find the 4th term of an arithmetic progression (AP) where the first term is 2 and the common difference is 0.5
    a) 0.5
    b) 2.5
    c) 3.5
    d) 4

  6. Cot θ can be expressed as:
    a) 1/sin θ
    b) 1/cos θ
    c) 1/tan θ
    d) tan θ

  7. Solve the inequality y + 9 > 5y – 7
    a) y > 4
    b) y > -4
    c) y < 4
    d) y < -4

  8. Find the distance between the points P (1,6) and Q (5,3)
    a) 6
    b) 5
    c) 4
    d) 3

  9. Find the sum of the first 12 terms of the arithmetic series 5 + 9 + 13 + …
    a) 612
    b) 702
    c) 119
    d) 324

  10. Solve the simultaneous equations 3x – y = 23 and 2x + 5y = 4 for y
    a) -20
    b) -2
    c) 2
    d) 7

  11. If 2ˣ = 4, find the value of x
    a) 5
    b) 10
    c) 12
    d) 9

  12. Find the square root of 400
    a) 20
    b) 200
    c) 40
    d) 2000

  13. If P = √(4 × 9 × 16), find the value of P
    a) 24
    b) 6
    c) 48
    d) 12

  14. Express 27^(-2/3)
    a) 9
    b) 1/9
    c) 0.9
    d) 1

  15. Simplify a⁶ × a⁻³
    a) a³
    b) a⁴
    c) a⁵
    d) a⁶

  16. Find the 40th term of the arithmetic sequence 6, 11, 16, 21, …
    a) 201
    b) 200
    c) 75
    d) 150

  17. Solve the equation (1/2)ˣ = 8 for x
    a) 3
    b) 6
    c) -3
    d) -6

  18. Simplify log₁₀(√8) / log₁₀(108)
    a) 1/3
    b) 1/2
    c) log₁₀(√2)
    d) 1/3 log₁₀(√8)

  19. Solve (x + 2)(x + 7) = 0
    a) x = 1 or 8
    b) x = -2 or 7
    c) x = -4 or 5
    d) x = -3 or 6

  20. The nth term of a sequence is given by (-1)ⁿ⁻² × 2ⁿ⁻¹. Find the sum of the second term
    a) 3
    b) 4
    c) 2
    d) 10

  21. Simplify log₅(8) / log₅(√8)
    a) -2
    b) -1/2
    c) 1/2
    d) 2

  22. Simplify (3√2 – 1)(3√2 + 1)
    a) 17
    b) 18
    c) 1
    d) 6

  23. If E = MN / (S + N) and E = 75, M = 120, N = 5000, find S
    a) 1000
    b) 200
    c) 3000
    d) 4000

  24. Simplify log₃(7) + log₃(15) – log₃(5)
    a) log₃(19)
    b) log₃(5)
    c) 3
    d) 1

  25. Find the common ratio of the geometric sequence 6, 12, 24, 48, …
    a) 6
    b) 12
    c) 2
    d) 48

  26. Divide 4x³ – 6x² + 2x + 7 by 2x – 3, find the quotient
    a) 6x + 8
    b) 2x² + 6x + 8
    c) 2x² + 6x
    d) 2x + 8

  27. Find the sum of the roots of the equation 2x² + 3x – 9 = 0
    a) -18
    b) -6
    c) 9/2
    d) -3/7

  28. Find the distance between A(3,2) and B(4,6)
    a) 5
    b) 4
    c) 3
    d) 2

  29. Find the common ratio of the geometric sequence 36, 12, 4, 4/3, …
    a) 3
    b) 1/3
    c) -3
    d) -1/3

  30. Find the equation of a straight line that passes through the points P(2, -3) and Q(-4, 2)
    a) y = 5x + 3
    b) y = -5/6x – 3
    c) y = -5/6x + 2
    d) y = 5/6x – 3


Section B: Theory Questions

  1. Determine if AB is parallel or perpendicular to PQ in the following cases:
    a) A(3,1), B(4,3), P(4,6), Q(5,8)
    b) A(5,1), B(3,2), P(2,4), Q(5,6)
    c) A(4,7), B(6,8), P(3,5), Q(5,6)

  2. Find the distance between the following pairs of points:
    a) A(3,2) and B(4,6)
    b) C(-1,3) and D(2,-7)
    c) P(5,-8) and Q(-4,-2)
    d) S(-3,-2) and T(1,-4)

  3. Find the equation of the straight line that passes through P(2,-3) and Q(-4,2).

  4. Find the common ratio in the following exponential sequences:
    a) 6, 12, 24, 48, …
    b) 36, 12, 4, 4/3, …
    c) 4, -8, 16, -32, …
    d) 54, -18, 6, -2, …

Further Mathematics SS 2 Second Term Examination – Answers and Explanations

Below are the correct answers to the questions, along with step-by-step explanations in simple language.


Section A: Objective Questions

1. Given that x = -3 and y = -7, evaluate (x² – y) / (y² – x)

First, we calculate the values inside the expression:

(-3)² – (-7) = 9 + 7 = 16

(-7)² – (-3) = 49 + 3 = 52

Now, we divide:

16 / 52 = 4 / 13

Answer: (C) 4/13


2. Solve the equation x² – 2x – 8 = 0

We factorize the equation:

(x – 4)(x + 2) = 0

Setting each bracket to zero:

x – 4 = 0 → x = 4

x + 2 = 0 → x = -2

Answer: (B) x = -2 or 4


3. The conjugate of 2 + √3 is:

In mathematics, the conjugate of a + b√c is a – b√c.

So, the conjugate of 2 + √3 is 2 – √3.

Answer: (D) 2 – √3


4. If f(x) = 10x – 3, find f(2).

Substituting x = 2 into the function:

f(2) = 10(2) – 3 = 20 – 3 = 17

Answer: (D) 17


5. Find the 4th term of an arithmetic sequence where the first term is 2 and the common difference is 0.5

Using the formula for the nth term of an arithmetic sequence:

Tn = a + (n-1)d

T4 = 2 + (4-1) × 0.5

= 2 + 1.5 = 3.5

Answer: (C) 3.5


6. Cot θ can be expressed as:

cotθ = cosθ / sinθ = 1 / tanθ

Answer: (C) 1/tanθ


7. Solve the inequality y + 9 > 5y – 7

Rearrange the equation:

y + 9 – 5y > -7

-4y > -16

Dividing by -4 (remember to reverse the inequality sign):

y < 4

Answer: (C) y < 4


8. Find the distance between P(1,6) and Q(5,3).

Using the distance formula:

d = √[(x₂ – x₁)² + (y₂ – y₁)²]

d = √[(5-1)² + (3-6)²]

d = √(16 + 9) = √25 = 5

Answer: (B) 5


9. Find the sum of the first 12 terms of the arithmetic sequence 5, 9, 13, …

Using the sum formula:

Sn = (n/2) [2a + (n-1)d]

S12 = (12/2) [2(5) + (12-1) × 4]

= 6 (10 + 44) = 6 × 54 = 324

Answer: (D) 324


10. Solve 3x – y = 23 and 2x + 5y = 4 for y.

Express y in terms of x:

y = 3x – 23

Substituting into the second equation:

2x + 5(3x – 23) = 4

2x + 15x – 115 = 4

17x = 119

x = 7

Substituting x into y = 3x – 23:

y = 3(7) – 23 = 21 – 23 = -2

Answer: (B) -2


11. If 2^x = 4, find x.

Since 4 = 2², we rewrite:

2^x = 2²

x = 2

Answer: (D) 2


12. Find the square root of 400.

√400 = 20

Answer: (A) 20


13. If P = √(4 × 9 × 16), find P.

P = √576 = 24

Answer: (A) 24


14. Express 27^(-2/3).

27 = 3³

(3³)^(-2/3) = 3^(-2) = 1/9

Answer: (B) 1/9


15. Simplify a⁶ × a⁻³.

a⁶ × a⁻³ = a^(6-3) = a³

Answer: (A) a³


16. Find the 40th term of the arithmetic sequence 6, 11, 16, 21, …

Tn = a + (n-1)d

T40 = 6 + (40-1) × 5

= 6 + 195 = 201

Answer: (A) 201


17. Solve (1/2)^x = 8 for x.

(2^(-1))^x = 2³

2^(-x) = 2³

  • x = 3

x = -3

Answer: (C) -3


18. Simplify log₁₀(√8) / log₁₀(108).

= (1/2) log₁₀ 8 / log₁₀ 108

= (1/3) / 1 = 1/3

Answer: (A) 1/3


19. Solve (x + 2)(x + 7) = 0.

x + 2 = 0 → x = -2

x + 7 = 0 → x = -7

Answer: (B) x = -2 or -7


20. The nth term of a sequence is given by (-1)ⁿ⁻² × 2ⁿ⁻¹. Find the second term.

T₂ = (-1)^(2-2) × 2^(2-1) = (1) × (2) = 2

Answer: (C) 2


This explanation provides clear, step-by-step solutions in simple language, making it easy for students and teachers to understand and apply these concepts in future problems.