CONVERTING FROM BASE TWO TO ANOTHER BASE (BINARY NUMBERS)

Subject:

MATHEMATICS

Term:

First Term

Week:

Week 1

Class:

JSS 3 / BASIC 9

Previous lesson: Pupils have previous knowledge of

BINARY OPERATIONS

that was taught in their previous lesson

Topic:

Number Bases:

1. (a) Conversion from base ten to other bases.
2. (b) Conversion from other bases to base ten.
3. (c) Conversion from one base to another other than base ten. (d) Number base arithmetic.

Behavioural Objectives:

At the end of the lesson, learners will be able to

• conversion from base ten to other bases.
• conversion from other bases to base ten.
• conversion from one base to another other than base ten.
• solve simple sums on number base arithmetic.

 

Instructional Materials:

• Wall charts
• Pictures
• Related Online Video
• Flash Cards

Methods of Teaching:

• Class Discussion
• Group Discussion
• Asking Questions
• Explanation
• Role Modelling
• Role Delegation

Reference Materials:

• Scheme of Work
• Online Information
• Textbooks
• Workbooks
• 9 Year Basic Education Curriculum
• Workbooks

 

CONTENT:

WEEK 1

 

TOPIC: NUMBER BASES

 

CONTENT:

• Concept and types of number base.
• Binary numbers.
• Conversion in number bases: Denary to Binary, Binary to Denary, Denary to other bases, One base to another, etc.
• Arithmetical operation in Binary System: Addition, Subtraction, Multiplication and Division.
• Bidecimal numbers: Conversion, Addition and Subtraction.
• Equation in number bases.

 

CONCEPT AND TYPES OF NUMBER BASES

 

Number Base is a system of counting natural numbers in bundles. Some languages have their own unique method or way of counting numbers while others have same method. For instance, numbers are counted in bundle of ten digits called base ten or denary.  The digits involved in English natural numbers are: 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Some unique number bases include: Base 2 (Binary), Base 8 (Octal), Base 10 (Denary or Decimal), Base 16 (Hexadecimal),… there are other bases such as base 3, base 4, base 5, base 6, etc. The bases of number systems are usually written as a subscript either in word or figure. Examples: 111011₂ or 111011_two, 5734₈ or 5734_eight, 781₁₀ or 781_ten, etc.

 

 

CLASS ACTIVITY:

Teachers should ask the students to count in their mother tongues.

Good morning, class! Today, we’re going to learn about the conversion of binary numbers (base two numbers) to denary numbers (base 10 numbers). Understanding this topic is essential because it helps us communicate and work with binary systems used in computers and digital electronics.

Now, let’s start by revisiting what binary numbers are. Binary is a number system that only uses two digits: 0 and 1. In contrast, our familiar denary (base 10) system uses ten digits from 0 to 9. The positions of these digits in a number determine their value based on powers of 10.

For example, in the denary system:
– 123 = (1 * 10^2) + (2 * 10^1) + (3 * 10^0)

Now, let’s move on to converting binary to denary. To do this, we follow a straightforward process:

Step 1: Write down the binary number.
Step 2: Assign each binary digit a positional value from right to left. The rightmost digit has a positional value of 2^0 (which is 1), and the positional value increases by a power of 2 as we move from right to left.
Step 3: Multiply each binary digit by its positional value.
Step 4: Add all the products from Step 3 together to get the denary equivalent.

Let’s work through an example to make this clearer. We’ll convert the binary number 10110 to denary:

Step 1: Write down the binary number 10110.

Step 2: Assign positional values to each digit from right to left:
– 0 at the rightmost has a positional value of 2^0 = 1
– 1 next to the right has a positional value of 2^1 = 2
– 1 next to the left has a positional value of 2^2 = 4
– 0 next to the left has a positional value of 2^3 = 8
– 1 at the leftmost has a positional value of 2^4 = 16

Step 3: Multiply each binary digit by its positional value:
– 0 * 1 = 0
– 1 * 2 = 2
– 1 * 4 = 4
– 0 * 8 = 0
– 1 * 16 = 16

Step 4: Add all the products from Step 3 together:
0 + 2 + 4 + 0 + 16 = 22

So, the binary number 10110 is equal to the denary number 22.

Now, practice this method with various examples on your own, and you’ll become more comfortable with converting binary to denary numbers. Remember, practice makes perfect! If you have any questions, feel free to ask. Happy learning!

BINARY NUMBERS.

 

Binary numbers are a system of counting numbers in base two. In binary system, the greatest digit is 1 and the least or lowest is 0. Hence, the two digits available in binary numbers are 1 and 0. Binary numbers is the most important number bases because of its usage in computer. Examples of binary numbers are 11111₂, 1000001_two, 0101₂, etc.

 

EXPRESSING BINARY AS SUM OF MULTIPLES

 

We can easily express any binary number as power of multiples of two as shown in the following examples.

1. 110_two ^{2 1 0})
2. 1111₂ ^{3 2 1}) ⁰)
3. 10001_tw0 ^{4 3 2}) ^{1 0}

 

CLASS ACTIVITY

Express each of the following as multiples of power of its base

(1) 1011_two       (2) 11000110_two      (3) 832_ten     (4) 890.701_ten

(5)100.1001_{two  (}6)   4302.42_six                      (7) 0.0247_eight

Converting binary numbers to denary numbers:

Example 1: Convert 1010 from binary to denary.
Step 1: Write down the binary number 1010.
Step 2: Assign positional values from right to left: 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3 = 8.
Step 3: Multiply each binary digit by its positional value: 0 * 1 = 0, 1 * 2 = 2, 0 * 4 = 0, 1 * 8 = 8.
Step 4: Add the products from Step 3: 0 + 2 + 0 + 8 = 10.
So, the binary number 1010 is equal to the denary number 10.

Example 2: Convert 11011 from binary to denary.
Step 1: Write down the binary number 11011.
Step 2: Assign positional values from right to left: 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16.
Step 3: Multiply each binary digit by its positional value: 1 * 1 = 1, 1 * 2 = 2, 0 * 4 = 0, 1 * 8 = 8, 1 * 16 = 16.
Step 4: Add the products from Step 3: 1 + 2 + 0 + 8 + 16 = 27.
So, the binary number 11011 is equal to the denary number 27.

Example 3: Convert 1001101 from binary to denary.
Step 1: Write down the binary number 1001101.
Step 2: Assign positional values from right to left: 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16, 2^5 = 32, 2^6 = 64.
Step 3: Multiply each binary digit by its positional value: 1 * 1 = 1, 0 * 2 = 0, 1 * 4 = 4, 1 * 8 = 8, 1 * 16 = 16, 0 * 32 = 0, 1 * 64 = 64.
Step 4: Add the products from Step 3: 1 + 0 + 4 + 8 + 16 + 0 + 64 = 93.
So, the binary number 1001101 is equal to the denary number 93.

Example 4: Convert 11100 from binary to denary.
Step 1: Write down the binary number 11100.
Step 2: Assign positional values from right to left: 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16.
Step 3: Multiply each binary digit by its positional value: 0 * 1 = 0, 0 * 2 = 0, 1 * 4 = 4, 1 * 8 = 8, 1 * 16 = 16.
Step 4: Add the products from Step 3: 0 + 0 + 4 + 8 + 16 = 28.
So, the binary number 11100 is equal to the denary number 28.

Example 5: Convert 1010111 from binary to denary.
Step 1: Write down the binary number 1010111.
Step 2: Assign positional values from right to left: 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16, 2^5 = 32, 2^6 = 64.
Step 3: Multiply each binary digit by its positional value: 1 * 1 = 1, 1 * 2 = 2, 1 * 4 = 4, 0 * 8 = 0, 1 * 16 = 16, 1 * 32 = 32, 1 * 64 = 64.
Step 4: Add the products from Step 3: 1 + 2 + 4 + 0 + 16 + 32 + 64 = 119.
So, the binary number 1010111 is equal to the denary number 119.

Keep practicing these conversions, and you’ll become more confident in working with binary and denary numbers. If you have any questions, feel free to ask!

CONVERSION OF BINARY NUMBERS TO DECIMAL NUMBERS

To express binary numbers in decimals or denary, we write the binary number as a sum of multiples of powers of two, or we multiply each digit by  the base and add to the next digit starting from the left.

NOTE: Any number or letter raised to the power of zero is 1

Examples:

1. Convert 1111_two to denary scale.

Solution:

1111_two ^{3 2 1}) ⁰)

_ten.

 

2. Express 11101_two as a decimal number

Solution:

11101_two ^{4 3 2}) ^{1 0}

_ten

 

3. Convert 1111110_two to a number in base ten.

Solution:

1111110_two ^{6 5 4}) ^{3 2}

^{1 0}

                                                _ten

 

CLASS ACTIVITY

Express the following binary numbers as denary numbers.

1. 110111_two 1010101010_two                    3. 10000000101_two

 

CONVERSION OF OTHER NUMBER BASES TO DENARY

 

Converting other number bases to denary is the same as that of binary discussed earlier. Let’s study the examples below.

 

1. Express 56_eight to denary

Solution:

56_eight ^{1 0} _ten

 

2. Convert 1243_five to base ten

Solution:

1243_five ^{3 2 1}) ⁰)

_ten

 

CLASS ACTIVITY

Express in denary the following number bases:

1. 124_eight 25_seven          3. 48_nine            4. 211_five

 

CONVERSION FROM DENARY TO ANY BASE

In converting a denary number to base two (binary) or any other base, we divide by that new base keeping the remainder in each step until there is nothing more to divide. The result is the list of remainders from the last to the first.

 

Example:                    

1. Convert 41_ten to base five
2. Convert 243_ten to base eight
3. Express 26₁₀ as binary number

 

Solution:

5	41		8	243		2	26
5	8 R 1		8	30 R 3		2	13 R 0
5	1R3		8	3 R 6		2	6 R 1
	0 R 1			0 R 3		2	3 R 0
						2	1 R 1
							0 R 1

41_{ten five}.            243_{ten eight}        26_{ten two}

 

CLASS ACTIVITY

Convert the following base ten numbers to the base indicated in brackets in front of each.

1. 344(base 7) 3256(base 5)           c. 7054(base 6)           d. 106(base 2)

 

CONVERTING FROM ONE BASE TO ANOTHER BASE OTHER THAN BASE 10

To do this, two steps are involved:

Step1: convert the given base to base ten.

Step2: convert the result gotten from step1 above to the required base.

converting 123410 to 2

The equation calculation formula for 123410 number to 2 is like this below.
2|1234
2|617|0
2|308|1
2|154|0
2|77|0
2|38|1
2|19|0
2|9|1
2|4|1
2|2|0
2|1|0
2|1|1
Ans:100110100102

 

CONVERTING FROM ONE BASE TO ANOTHER BASE OTHER THAN BASE 10

We can convert from one base to another base, other than Base 10, using the following steps:

1. Convert the given number into its Base 10 equivalent.

2. Divide the Base 10 number by the new base.

3. Write down the remainder.

4. Divide the quotient by the new base.

5. Write down the remainder.

6. Repeat Step 4 until the quotient is equal to 0.

7. The remainders are the digits of the new number in reverse order.

For example, let’s convert the number “1234” from Base 10 to Base 2 (Binary).

1. 1234 = 1 x 10^3 + 2 x 10^2 + 3 x 10^1 + 4 x 10^0

2. 1234 / 2 = 617 Remainder 0

3. 617 / 2 = 308 Remainder 1

4. 308 / 2 = 154 Remainder 0

5.154 / 2 = 77 Remainder 0

6. 77 / 2 = 38 Remainder 1

7. 38 / 2 = 19 Remainder 0

8. 19 / 2 = 9 Remainder 1

9. 9 / 2 = 4 Remainder 1

10. 4 / 2 = 2 Remainder 0

11. 2 / 2 = 1 Remainder 0

12. 1 / 2 = 0 Remainder 1

13. The remainders in reverse order are 10011010010. Therefore, 1234 in Base 10 is equal to 10011010010 in Base 2 (Binary).

Now let’s convert the number “1234” from Base 10 to Base 8 (Octal).

1. 1234 = 1 x 10^3 + 2 x 10^2 + 3 x 10^1 + 4 x 10^0

2. 1234 / 8 = 308 Remainder 2

3. 308 / 8 = 38 Remainder 6

4. 38 / 8 = 4 Remainder 6

5. 4 / 8 = 0 Remainder 4

6. The remainders in reverse order are 2466. Therefore, 1234 in Base 10 is equal to 2466 in Base 8 (Octal).

 

Example:

1. Convert 10111_two to base 6

Solution:

Step1: we first convert 10111_two to base ten.

10111_two ^{4 3 2}) ^{1 0}

_ten

Step2: we now convert 23_ten to base 6

 

6	23
6	3 R 5
	0 R 3

_two 23_{ten six}

 

2. Convert 3041_five to base four.

Solution:

First convert 3041_five to base 10

3041_five ^{3 2 1}) ⁰

_ten

Now, convert 395_ten  to base 4.

4	395
4	98 R 3
4	24 R 2
4	6 R 0
4	1 R 2
	0 R 1

3041_five  395_ten 12023_four

 

CLASS ACTIVITY

Convert: (a) 405₆ to a binary number   (b) 321₄ to octal scale(c) 654₈ to base three.

 

BICIMAL NUMBERS.

Bicimals are binary numbers in fractional form in which the denominator is a power of 2. Examples include 10.101₂, 0.111₂, 1011.1101₂, etc.

Good morning, class! Today, we’ll be diving into the topic of converting denary numbers (base 10) to binary numbers (base 2). This skill is essential because it helps us understand how computers and digital systems represent and process information using the binary number system.

Let’s begin with a quick recap of what denary and binary numbers are. In the denary system, we use ten digits from 0 to 9 to represent numbers. For example, the denary number 35 represents three tens and five units (3 * 10 + 5). On the other hand, the binary system only uses two digits: 0 and 1. Each digit’s position in a binary number represents a power of 2.

Now, let’s learn the step-by-step process of converting denary numbers to binary:

Step 1: Start with the given denary number.
Step 2: Divide the denary number by 2.
Step 3: Note the remainder (either 0 or 1) when dividing by 2, which represents the rightmost binary digit.
Step 4: Continue dividing the quotient from Step 2 by 2, noting the remainders each time, until the quotient becomes zero.
Step 5: Write the remainders obtained in reverse order to get the binary equivalent.

Let’s work through an example to illustrate the process. We’ll convert the denary number 13 to binary:

Step 1: Start with the denary number 13.
Step 2: Divide 13 by 2. The quotient is 6, and the remainder is 1.
Step 3: Write down the remainder (1) as the rightmost digit of the binary number.
Step 4: Divide the quotient (6) by 2. The new quotient is 3, and the remainder is 0.
Step 5: Write down the remainder (0) to the left of the previous digit.
Step 6: Divide the new quotient (3) by 2. The new quotient is 1, and the remainder is 1.
Step 7: Write down the remainder (1) to the left of the previous digits.
Step 8: Divide the new quotient (1) by 2. The quotient is now 0, and the remainder is 1.
Step 9: Write down the remainder (1) to the left of the previous digits.

Now, read the remainders in reverse order from Step 9 to Step 3:
Binary number = 1101

So, the denary number 13 is equivalent to the binary number 1101.

Great job, class! Now, practice this process with different denary numbers on your own to become more proficient in converting denary to binary. If you have any questions, don’t hesitate to ask. Happy learning!

CONVERSION OF BICIMAL TO DENARY

 

When converting a bicimal number to denary, the process is quite simple. All you need to do is take the value of each digit and multiply it by the corresponding power of two. For example, when converting the bicimal number 1101 (which has a value of 13 in denary), you would take 1 and multiply it by 2^3, take 1 and multiply it by 2^2, take 0 and multiply it by 2^1, and finally take 1 and multiply it by 2^0. When you add up all of these values, you get the final answer of 13.

Interestingly, this same process can be used to convert a denary number to bicimal. To do this, you simply take the value of each digit and divide it by the corresponding power of two. For example, when converting the denary number 13 to bicimal, you would take 1 and divide it by 2^3, take 1 and divide it by 2^2, take 0 and divide it by 2^1, and finally take 1 and divide it by 2^0. When you add up all of these values, you get the final answer of 1101 (which is 13 in bicimal).

In converting bicimal numbers to denary, we write the bicimal numbers as a sum of multiples of powers of two. The whole numbers parts of bicimal are raised to positive power of 2 increasing to the left starting with zero. While the fractional part are raised to negative power of 2 decreasing to the left starting with negative 1 .

101 . 1001

 

 

Whole number part   Fractional number part

 

Examples:

Convert the following to denary:

101. 11₂ b. 0.11₂            c. 111.011₂

Solutions:

101. 11₂ ^{2 1 0}) ^{-1 -2}

)_ten oR _ten.

 

1. 11₂ ⁰) ^-1) ^-2)

_ten

111. 011₂ ^{2 1 0}) ^{-1 -2 -3}

_{ten ten}.

NOTE: Other bases in fractional form other than bicimal can also be expressed in denary using the same method as in bicimal. Teacher should teach the students using the repeated method of converting number bases to base ten(denary).

 

EVALUATION:

Convert each of the following to denary scale.

101. 1011₂ 3256₈           c. 101.101₂      d. 43.21₈          e. 32.21₅          f. 532₉.

 

ARITHMETIC OPERATIONS IN NUMBER

Basic operations of addition, subtraction, multiplication and division are carried out in other bases exactly the same as base 10.

 

ADDITION IN BINARY SYSTEM

The binary number system is a base 2 system that uses only the digits 0 and 1 to represent all numbers. Because of its simplicity, the binary number system is used in many modern technologies, including computer hardware and software.

To add two binary numbers, start by aligning them on the right side so that their least significant digits are lined up. Then, add the numbers column by column, starting with the rightmost column. If the sum of a column is 2 or more, carry over the extra 1 to the next column.

For example, to add 101 + 100:

Align the numbers on the right side:

101

+ 100

_____

Start with the rightmost column and add the numbers:

101

+ 100

_____

001

The sum of the rightmost column is 1, so there is no need to carry over.

Move to the next column on the left and add the numbers:

101

+ 100

_____

0101

The sum of this column is 5, so carry over the 1 to the next column:

101

+ 100

_____

00101

Continue moving to the left and adding the numbers until all columns have been added:

101

+ 100

_____

11001

____

11

The final sum is 11001.

To add in binary number, the following steps are important:

1. Arrange the numbers as in the addition of decimal numbers.
2. Add the elements of the column starting with the right most column.
3. Divide the sum by two.
4. Record the remainder, which is either 0 or 1.
5. Add the quotient to the sum of the next column and repeat the process for the next column.

 

NOTE:

. Teachers should explain addition principle in binary numbers to the students using appropriate illustrations.

 

Examples:

 

1. Add 111_two to 11_two

Solution:

1          1          1

1          1

1          0          1          0₂

 

 

2. 11011₂ 10101₂ 1001₂

Solution:

1         1         0       1      1

1         0        1        0      1

1         0        0      1

1    1     1 0        0       0      1_two

 

 

ADDITION IN OTHER BASES:

The same principle applied when performing addition in binary and denary is applicable here also.

Examples:

1. Add 40002_five to 3403_five

 

Solution:

4          0          0          0          2

+          3          4          0          3

4          3          4          1          0_five

 

2. Find the sum of 2332_four and 302_four.

 

Solution:

2          3          3          2

+          3          0          2

3          3          0          0_four

 

 

 

3. Table of addition in base nine:

	0	1	2	3	4	5	6	7	8
0	0	1	2	3	4	5	6	7	8
1	1	2	3	4	5	6	7	8	10
2	2	3	4	5	6	7	8	10	11
3	3	4	5	6	7	8	10	11	12
4	4	5	6	7	8	10	11	12	13
5	5	6	7	8	10	11	12	13	14
6	6	7	8	10	11	12	13	14	15
7	7	8	10	11	12	13	14	15	16
8	8	10	11	12	13	14	15	16	17

 

NOTE: Teachers should solve more examples that includes adding in different bases, addition with missing numbers or digit in diferent bases.

 

CLASS ACTIVITY

Evaluate the following:

1. 1011_{2 2}
2. 100_{2 2} 10111₂
3. Find the sum of 246₇ and 836₁₀ give your answer in base seven.
4. Find the missing numbers in the following sums in base two.
5. 1 0          1          0          1          1      0          1          1

• * *          *          *               *     *          *          *

1    1          1          1          0               1     1          1          0

 

 

SUBTRACTION IN BASE TWO AND OTHER BASES

Subtractions in binary numbers are the same as subtraction in denary numbers. When the digit of the number to be subtracted is larger than the corresponding digit above it, we transfer one 2 from the next left column. If the immediate next column has zero digit, the transfer will be from further left column. The same principle is applicable to other bases other than base 2.

 

Examples:

1. Subtract 101₂ from 111₂

Solution:

1          1          1

1          0          1

1          0_two

 

 

2. By how much is 3767_eight greater than 2653_eight?

Solution:

3          7          6          7

–           2          6          5          3

1          1          1          4_eight

 

 

3. Find the missing numbers in this subtraction in base 2

1          1          1          1          1          1

*          *          *          *          *          *

1          0          1          0          1_two

Solution:

We subtract 10101₂  from 111111₂ to get the missing numbers.

Hence, 111111_{2 2 2}

Therefore, the missing numbers is ₂

 

4. If 234­_{five five} 434_five = 2304_five, find

Solution:

= 2304_five  (234­_five 434_five)

= 2304_five  (1223_five)

= 1031_five

 

NOTE: Teachers should explain this technique used in examples3 and 4 above with more examples.

 

MULTIPLICATION AND DIVISION OF NUMBER BASES

MULTIPLICATION is a repeated addition. This principle is always applied while multiplying binary numbers and other number bases. The important thing we must note is that if we are working in base two and other bases, all the figures we use in the working should be less than 2 or the number base under consideration.

 

Examples:

1. Simplify 1101₂ 111₂

Solution:

1          1          0          1

1          1          1

1          1          0          1

1          1          0          1

1          1          0          1

1          0          1          1          0          1          1_two

 

1101₂  111₂  1011011_two

 

2. Base 5 multiplication table.

	0	1	2	3	4
0	0	0	0	0	0
1	0	1	2	3	4
2	0	2	4	11	13
3	0	3	11	14	22
4	0	4	13	22	31

 

DIVISION in base two is very similar to division in base ten. If the two numbers are in the same base, we divide using the long division method. However, if both numbers are not in the same base, we convert to base ten and then to the base required before solving.

 

Examples:

1. Divide 10100₂ by 100₂

 

Solution:

Method1

Convert  both numbers to base 10 and divide , then convert back to base 2.

10100₂ = 20₁₀ and 100₂ = 4₁₀

20_{10 10} = 5₁₀

5₁₀ = 101₂

 

Method2:

Long division.

101

10100

100      100

100

100

000

10100₂  100₂ = 101₂

 

PRACTICE EXERCISE

1. Find the product of the following
2. 11101₂ and 111₂ 415₆ and 54₆  c. 2010₁₁ and 10₁₀
3. Evaluate 111010₂ 1001₂
4. Complete the table in base seven

 

	1	2	5	6
1	1	2		6
2	2	4	13
5	5	13	34
6	6			51

 

ASSIGNMENT

1. Express each of the following numbers in binary
2. a) 234_six b) 0.75_ten c) 73.5_nine
3. Convert each of the following binary numbers to base ten.
4. a) 100.1111 b) 111 111
5. Convert each of the following base ten numbers to binary
6. a) 623 b) 20 c) 112. 125
7. Simplify 11_two x 1011_two – 111_two.
8. If 100_two x y = 1100_two, find the value of y.

 

PRESENTATION:

Step 1:

The subject teacher revises the previous topic

Step 2:

He or she introduces the new topic

 

Step 3:

The class teacher allows the pupils to give their own examples and he corrects them when the needs arise

[mediator_tech]

Evaluation

Question 1: Convert the denary number 47 to binary.
a) 101101
b) 101111
c) 110111

Question 2: Convert the binary number 11010 to denary.
a) 22
b) 26
c) 28

Question 3: The binary number system uses digits ______ and _______.
a) 0, 1
b) 1, 2
c) 0, 2

Question 4: Convert the denary number 95 to binary.
a) 1011010
b) 1011110
c) 1011111

Question 5: In the denary system, we use ______ digits from 0 to 9.
a) 5
b) 8
c) 10

Question 6: Convert the binary number 111001 to denary.
a) 49
b) 57
c) 63

Question 7: The binary equivalent of the denary number 15 is ______.
a) 1111
b) 1010
c) 1101

Question 8: Convert the denary number 123 to binary.
a) 1011010
b) 1111011
c) 1101110

Question 9: The binary number 10011 is equivalent to the denary number ______.
a) 8
b) 15
c) 19

Question 10: The denary equivalent of the binary number 100110 is ______.
a) 18
b) 38
c) 22

Question 11: Convert the denary number 56 to binary.
a) 110000
b) 111000
c) 101100

Question 12: The binary number 1101 is equivalent to the denary number ______.
a) 12
b) 13
c) 14

Question 13: Convert the denary number 75 to binary.
a) 1001010
b) 1001101
c) 1010110

Question 14: The denary equivalent of the binary number 11110 is ______.
a) 30
b) 31
c) 32

Question 15: The binary number system uses the base ______.
a) 5
b) 2
c) 10

Make sure to carefully read each question and select the correct option (a, b, or c) to complete the fill-in-the-blank statements. Good luck, and don’t hesitate to ask if you need any assistance!

 

Suggested Solution

Let’s go through the questions one by one and provide the detailed workings:

Question 1: Convert the denary number 47 to binary.
Solution:
Step 1: Divide 47 by 2. The quotient is 23, and the remainder is 1.
Step 2: Divide 23 by 2. The quotient is 11, and the remainder is 1.
Step 3: Divide 11 by 2. The quotient is 5, and the remainder is 1.
Step 4: Divide 5 by 2. The quotient is 2, and the remainder is 1.
Step 5: Divide 2 by 2. The quotient is 1, and the remainder is 0.
Step 6: Divide 1 by 2. The quotient is 0, and the remainder is 1.

Reading the remainders from bottom to top: 47 in binary is 101111.

Answer: b) 101111

Question 2: Convert the binary number 11010 to denary.
Solution:
11010 in binary can be expressed as:
(1 * 2^4) + (1 * 2^3) + (0 * 2^2) + (1 * 2^1) + (0 * 2^0) = 16 + 8 + 0 + 2 + 0 = 26

Answer: b) 26

Question 3: The binary number system uses digits ______ and _______.
Solution:
a) 0, 1

Answer: a) 0, 1

Question 4: Convert the denary number 95 to binary.
Solution:
Step 1: Divide 95 by 2. The quotient is 47, and the remainder is 1.
Step 2: Divide 47 by 2. The quotient is 23, and the remainder is 1.
Step 3: Divide 23 by 2. The quotient is 11, and the remainder is 1.
Step 4: Divide 11 by 2. The quotient is 5, and the remainder is 1.
Step 5: Divide 5 by 2. The quotient is 2, and the remainder is 1.
Step 6: Divide 2 by 2. The quotient is 1, and the remainder is 0.
Step 7: Divide 1 by 2. The quotient is 0, and the remainder is 1.

Reading the remainders from bottom to top: 95 in binary is 1011111.

Answer: c) 1011111

Question 5: In the denary system, we use ______ digits from 0 to 9.
Solution:
c) 10

Answer: c) 10

Question 6: Convert the binary number 111001 to denary.
Solution:
111001 in binary can be expressed as:
(1 * 2^5) + (1 * 2^4) + (1 * 2^3) + (0 * 2^2) + (0 * 2^1) + (1 * 2^0) = 32 + 16 + 8 + 0 + 0 + 1 = 57

Answer: b) 57

Question 7: The binary equivalent of the denary number 15 is ______.
Solution:
15 in binary can be expressed as:
(1 * 2^3) + (1 * 2^2) + (1 * 2^1) + (1 * 2^0) = 8 + 4 + 2 + 1 = 15

Answer: a) 1111

Question 8: Convert the denary number 123 to binary.
Solution:
Step 1: Divide 123 by 2. The quotient is 61, and the remainder is 1.
Step 2: Divide 61 by 2. The quotient is 30, and the remainder is 1.
Step 3: Divide 30 by 2. The quotient is 15, and the remainder is 0.
Step 4: Divide 15 by 2. The quotient is 7, and the remainder is 1.
Step 5: Divide 7 by 2. The quotient is 3, and the remainder is 1.
Step 6: Divide 3 by 2. The quotient is 1, and the remainder is 1.
Step 7: Divide 1 by 2. The quotient is 0, and the remainder is 1.

Reading the remainders from bottom to top: 123 in binary is 1111011.

Answer: b) 1111011

Question 9: The binary number 10011 is equivalent to the denary number ______.
Solution:
10011 in binary can be expressed as:
(1 * 2^4) + (0 * 2^3) + (0 * 2^2) + (1 * 2^1) + (1 * 2^0) = 16 + 0 + 0 + 2 + 1 = 19

Answer: c) 19

Question 10: The denary equivalent of the binary number 100110 is ______.
Solution:
100110 in binary can be expressed as:
(1 * 2^5) + (0 * 2^4) + (0 * 2^3) + (1 * 2^2) + (1 * 2^1) + (0 * 2^0) = 32 + 0 + 0 + 4 + 2 + 0 = 38

Answer: b) 38

Question 11: Convert the denary number 56 to binary.
Solution:
Step 1: Divide 56 by 2. The quotient is 28, and the remainder is 0.
Step 2: Divide 28 by 2. The quotient is 14, and the remainder is 0.
Step 3: Divide 14 by 2. The quotient is 7, and the remainder is 0.
Step 4: Divide 7 by 2. The quotient is 3, and the remainder is 1.
Step 5: Divide 3 by 2. The quotient is 1, and the remainder is 1.
Step 6: Divide 1 by 2. The quotient is 0, and the remainder is 1.

Reading the remainders from bottom to top: 56 in binary is 111000.

Answer: b) 111000

Question 12: The binary number 1101 is equivalent to the denary number ______.
Solution:
1101 in binary can be expressed as:
(1 * 2^3) + (1 * 2^2) + (0 * 2^1) + (1 * 2^0) = 8 + 4 + 0 + 1 = 13

Answer: b) 13

Question 13: Convert the denary number 75 to binary.
Solution:
Step 1: Divide 75 by 2. The quotient is 37, and the remainder is 1.
Step 2: Divide 37 by 2. The quotient is 18, and the remainder is 1

Step 3: Divide 18 by 2. The quotient is 9, and the remainder is 0.
Step 4: Divide 9 by 2. The quotient is 4, and the remainder is 1.
Step 5: Divide 4 by 2. The quotient is 2, and the remainder is 0.
Step 6: Divide 2 by 2. The quotient is 1, and the remainder is 0.
Step 7: Divide 1 by 2. The quotient is 0, and the remainder is 1.

Reading the remainders from bottom to top: 75 in binary is 1001011.

Answer: a) 1001011

Question 14: The denary equivalent of the binary number 11110 is ______.
Solution:
11110 in binary can be expressed as:
(1 * 2^4) + (1 * 2^3) + (1 * 2^2) + (1 * 2^1) + (0 * 2^0) = 16 + 8 + 4 + 2 + 0 = 30

Answer: a) 30

Question 15: The binary number system uses the base ______.
Solution:
b) 2

Answer: b) 2

Great job, class! You’ve successfully solved the fill-in-the-blank questions related to converting denary numbers to binary numbers. Keep practicing and exploring more topics in mathematics. If you have any more questions or need further clarification, feel free to ask. Happy learning!

[mediator_tech]

CONCLUSION:

The subject goes round to mark the pupil’s notes. He does the necessary corrections